Boot AArch64 in easy way

My work often requires booting AArch64 fast models. As there are two of them and each has different arguments I decided to write simple script to handle that.

Script takes three arguments:

  • kernel
  • rootfs (can be skipped)
  • model type (foundation/rtsm — first one as default)

This is work in progress — for example there is no network configured for RTSM yet. But I hope that it will be useful for other users.

#!/bin/bash

model=foundation
kernel=
rootfs=

if [ ! -z $3 ]; then
        model=full
fi

if [ -z $1 ]; then
        echo "Usage: boot-armv8 KERNEL ROOTFS"
else
        kernel=`realpath $1`
fi

if [ ! -z $2 ]; then
        rootfs=`realpath $2`
fi

case $model in
        foundation)
                if [ ! -z $rootfs ];then
                        rootfs=" --block-device $rootfs"
                fi
                sudo ip tuntap add tap0 mode tap
                sudo ifconfig tap0 192.168.168.1
                ~/devel/canonical/aarch64/FastModels/Foundation_v8pkg/Foundation_v8 \
                        --image $kernel \
                        --network bridged --network-bridge=tap0 \
                        $rootfs
                ;;
        rtsm)
                if [ ! -z $rootfs ];then
                        rootfs=" -C motherboard.mmc.p_mmc_file=$rootfs "
                fi
                export ARMLMD_LICENSE_FILE=8224@flexlm.linaro.org
                ~/devel/canonical/aarch64/FastModels/VE/AEMv8_0.8.4407/ModelDebugger_7.1/bin/model_shell64 \
                        -a $kernel \
                        $rootfs \
                        ~/devel/canonical/aarch64/FastModels/VE/AEMv8_0.8.4407/lib/Linux64/RTSM_VE_AEMv8A.so
                ;;
esac